Grade 12th passModern Physics

Monochromatic light of frequency 6.0x10^14 Hz is produced by a laser. The power emitted is 2x10^-3 W. The number of photons emitted, on the average, by the source per second is?

Nikhila Thakur

9 Years agoGrade 12th pass

2 Answers

Yogesh Saravanan

Approved Tutor Answer9 Years ago

energy of one photon is = h* freq

power is the energy per unit time

therfore the energy given per second is 2 * 10^-3

number of photons * energy of one photon = total energy

number of photons = (2*10^-3)/(6.636*10^-34 * 6 * 10^14)

approxi mately = 5 * 10^15 photons .

Yash Chourasiya

6 Years ago

Dear Student

An energy,
E = hv
E= 6.63×10^–34 x 6.05×10¹⁴
E = 3.98×10^–19J
Now, number of photons emitted per second n = p/E
= 2.0 x 10^-3/3.98 x 10^-19J
= 5 x 10¹⁵photons per second.

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya

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Monochromatic light of frequency 6.0x10^14 Hz is produced by a laser. The power emitted is 2x10^-3 W. The number of photons emitted, on the average, by the source per second is?

Nikhila Thakur

2 Answers

Yogesh Saravanan

Yash Chourasiya

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