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Grade 12th passModern Physics

Light of 500nm is incident on a metal with work function 2.28ev .The de broglie wavelength of the emitted electron is
1) less than 2.8 ×10*-12m
2)less than 2.8×10*-10m
3) less than 2.8×10*-9m
4) greater than 2.8 ×10*9m

Profile image of sheema
9 Years agoGrade 12th pass
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1 Answer

Profile image of Physics Expert
8 Years ago
Calculate the energy of the photon.


Calculate the maximum kinetic energy as per the Einstein photoelectric emmission.

Calculate the debroglie wavelength by the equation as below.


Hence, the correct option is B.