sonika p
Last Activity: 7 Years ago
let c = xi+yj+zk
given the two vectors are coplanar, thus their determinant is zero.
equating the det to zero be get, -x+y+z=0
x=y+z.....(1)
and c is perpendicular to a, thus a.c=0
2x+y+z=0....(2)
from equation 1 and 2 we get, x=0
now, c is a unit vector, thus x2+y2+z2=1....(3)
and y+z=0...(4)
solving equations 3 and 4 we get y=+/- (1/root2)
thus z = -/+(1/root2)
thus c = (1/root2) j – (1/root2) k
or c = – (1/root2) j + (1/root2) k