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Input volatge is 20 volt. V across base emmitter 0 Across collector emiitor 0 Value of Ic Ib and beta
Dear studentAnswer is (3)Ib = vi/ rb = 40 u ampIc = 20 / rc = 5 m ampBeta = ic/ib= 125Regards
Dear student Apply KVL across base and emitter junction , Vi - 500ib = 0 20 = 500ib ib = 1/25 mA We can apply KCL across collector and emitter terminal because voltage across collector emitter =0 V so , 20 - 4ic = 0 ic = 5mA Hope this will help Good Luck
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