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Grade: 12th pass

                        

Input volatge is 20 volt. V across base emmitter 0 Across collector emiitor 0 Value of Ic Ib and beta

8 months ago

Answers : (2)

Saurabh Koranglekar
askIITians Faculty
10233 Points
							Dear student

Answer is (3)

Ib = vi/ rb = 40 u amp
Ic = 20 / rc = 5 m amp

Beta = ic/ib
= 125

Regards
8 months ago
Vikas TU
13786 Points
							
Dear student 
Apply KVL across base and emitter junction , 
Vi - 500ib = 0 
20 = 500ib 
ib = 1/25 mA 
We can apply KCL across collector and emitter terminal because 
voltage across collector emitter =0 V 
so , 20 - 4ic = 0 
ic = 5mA 
Hope this will help 
Good Luck 
8 months ago
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