Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Input volatge is 20 volt.V across base emmitter 0 Across collector emiitor 0 Value of Ic Ib and beta
Dear studentAnswer is (3)Ib = vi/ rb = 40 u ampIc = 20 / rc = 5 m ampBeta = ic/ib= 125Regards
Dear student Apply KVL across base and emitter junction , Vi - 500ib = 0 20 = 500ib ib = 1/25 mA We can apply KCL across collector and emitter terminal because voltage across collector emitter =0 V so , 20 - 4ic = 0 ic = 5mA Hope this will help Good Luck
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -