In scattering experiment, find the distance of closest approach, if a 6 MeV alpha-particle is used 1) 3.2*10^-16 m 2) 2*10^-14 m 3) 4.6*10^-15 m 4) 3.2*10^-15 m I know the formula I am only confused about the value of Z to be substituted. please solve and explain properly !

Question

Arun · Answer

Dear student Assume the nucleus to be the copper. hence z = 29 Hope it helps Regards Arun (askIITians forum expert)

Shivi . · Answer

Why to take copper only why not some other element? Please if someone can explain this as to why take copper and if not copper which other element can we take

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In scattering experiment, find the distance of closest approach, if a 6 MeV alpha-particle is used 1) 3.210^-16 m 2) 210^-14 m 3) 4.610^-15 m 4) 3.210^-15 m I know the formula I am only confused about the value of Z to be substituted. please solve and explain properly !

In scattering experiment, find the distance of closest approach, if a 6 MeV alpha-particle is used
1) 3.210^-16 m 2) 210^-14 m
3) 4.610^-15 m 4) 3.210^-15 m

I know the formula I am only confused about the value of Z to be substituted. please solve and explain properly !

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In scattering experiment, find the distance of closest approach, if a 6 MeV alpha-particle is used 1) 3.2*10^-16 m 2) 2*10^-14 m 3) 4.6*10^-15 m 4) 3.2*10^-15 m I know the formula I am only confused about the value of Z to be substituted. please solve and explain properly !

In scattering experiment, find the distance of closest approach, if a 6 MeV alpha-particle is used 1) 3.2*10^-16 m 2) 2*10^-14 m 3) 4.6*10^-15 m 4) 3.2*10^-15 m I know the formula I am only confused about the value of Z to be substituted. please solve and explain properly !

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In scattering experiment, find the distance of closest approach, if a 6 MeV alpha-particle is used 1) 3.210^-16 m 2) 210^-14 m 3) 4.610^-15 m 4) 3.210^-15 m I know the formula I am only confused about the value of Z to be substituted. please solve and explain properly !

In scattering experiment, find the distance of closest approach, if a 6 MeV alpha-particle is used
1) 3.210^-16 m 2) 210^-14 m
3) 4.610^-15 m 4) 3.210^-15 m

I know the formula I am only confused about the value of Z to be substituted. please solve and explain properly !