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In scattering experiment, find the distance of closest approach, if a 6 MeV alpha-particle is used 1) 3.2*10^-16 m 2) 2*10^-14 m 3) 4.6*10^-15 m 4) 3.2*10^-15 m I know the formula I am only confused about the value of Z to be substituted. please solve and explain properly !

In scattering experiment, find the distance of closest approach, if a 6 MeV alpha-particle is used 
1) 3.2*10^-16 m   2) 2*10^-14 m 
3) 4.6*10^-15 m   4) 3.2*10^-15 m
 
I know the formula I am only confused about the value of Z to be substituted. please solve and explain properly !

Grade:12th pass

2 Answers

Arun
25750 Points
5 years ago
Dear student
 
Assume the nucleus to be the copper.
 
hence z = 29
 
Hope it helps
 
Regards
Arun (askIITians forum expert)
Shivi .
28 Points
5 years ago
Why to take copper only why not some other element?
Please if someone can explain this as to why take copper and if not copper which other element can we take 

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