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Grade: 12th pass
        
In scattering experiment, find the distance of closest approach, if a 6 MeV alpha-particle is used 
1) 3.2*10^-16 m   2) 2*10^-14 m 
3) 4.6*10^-15 m   4) 3.2*10^-15 m
 
I know the formula I am only confused about the value of Z to be substituted. please solve and explain properly !
8 months ago

Answers : (2)

Arun
22800 Points
							
Dear student
 
Assume the nucleus to be the copper.
 
hence z = 29
 
Hope it helps
 
Regards
Arun (askIITians forum expert)
8 months ago
Shivi .
28 Points
							
Why to take copper only why not some other element?
Please if someone can explain this as to why take copper and if not copper which other element can we take 
8 months ago
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