in order to decrease radioactive nuclei to one million of its initial number,number of half lives required is

Question

Vikas TU · Answer

Dear Student,
For the firrst order of chemcial kinetics,
t=2.303log(a/a-x)/l
=>t=2.303log(a/a-10⁶)/l
no of half lives=t/t_1/2=(2.303log(a/a-10⁶)/l)/(0.693/l) (since t_1/2=0.693/l)
no of half lives can be found by substituting a which is the initial number that is not given in the question.

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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in order to decrease radioactive nuclei to one million of its initial number,number of half lives required is

in order to decrease radioactive nuclei to one million of its initial number,number of half lives required is

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