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In carbon monoxide d carbon n d oxygen atoms r seprated by d dist 1.2 angstrom the c.o.mfrm d carbon atom is

In carbon monoxide d carbon n d oxygen atoms r seprated by d dist 1.2 angstrom the c.o.mfrm d carbon atom is

Grade:11

1 Answers

Arun
25763 Points
3 years ago
The Carbon Oxygen bond behave like a weight with Carbon and Oxygen at two ends. Now the distance of carbon atom is directly proportional to the mass of carbon atom. Let us consider distance from carbon atom to be `x` Angstrom so distance of oxygen atom will be (1.2 - x) Angstrom. Therfore, 12 (mass of carbon atom) ÷ 16 (mass of oxygen atom)= (1.2-) ÷ (x)After calculation we get x = 0.685 Angstrom

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