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Grade 12th passModern Physics

In an ore containing uranium the ratio of U238 to Pb206 is 3. Calculate the age of ore assuming that all lead present in ore is final stable product of U238 .Take the half-life of U238 to be 4.5x10^9yr this was answered by your group but how a/a-x became 4/3 when they said a/a-x is 3

Rohan

7 Years agoGrade 12th pass

1 Answer

Arun

7 Years ago

Please find the answer to your question

Number of atoms of ²³⁸U initially / Numbarof atoms of ²³⁸U finally = 4 / 3 = a / (a - x)

[∵ Initially one part lead is present with three parts Uranium]

∴ t = 2.303 / λ log α / (α – x )= 2.303 x 4. 5 x 10⁹ / 0.693 log 4/3

= 1.868 x 10⁹ years.

Hope it helps now

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