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Grade 10Modern Physics

In an experiment on photoelectric effect, light of wavelength 400 nm is incident on a cesium plate at the rate of 5.0 W. The potential of the collector plate is made sufficiently positive with respect to the emitter so that the current reaches its saturation value. Assuming that on the average one out of every 10^6 photons is able to eject a photoelectron, find the photocurrent in the circuit.

Profile image of Hrishant Goswami
12 Years agoGrade 10
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1 Answer

Profile image of Deepak Patra
12 Years ago
Sol. λ = 400 nm, P = 5 w E of 1 photon = hc/λ = (1242/400) ev No.of electrons = 5/Energy of 1 photon = 5 * 400/1.6 * 10^-19 * 1242 No.of electrons = 1 per 10^6 photon. No.of photoelectrons emitted = 5 * 400/1.6 * 1242 * 10^-19 * 10^6 Photo electric current = 5 * 400/1.6 * 1242 * 10^6 * 10^-19 * 1.6 * 10^-19 = 1.6 * 10^-6 A = 1.6 μA.

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