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In an experiment for measuring e/m ratio a cathode particle is passing through two deflecting plates maintained at voltage difference of 40V & separated by distance of 2cm.The cathode particle travelling at right angle to the field moves in a circular path of radius 2m.Determine the KE of electron in eV.

Amit Saxena , 12 Years ago
Grade upto college level
anser 1 Answers
Askiitians Tutor Team

To determine the kinetic energy (KE) of the electron in electron volts (eV) from the given parameters of the experiment, we can follow a systematic approach. The key points to consider are the voltage difference across the deflecting plates and the radius of the circular path the electron takes due to the electric field created by the plates.

Understanding the Relationship Between Voltage and Kinetic Energy

The kinetic energy of an electron can be derived from the work done on it by the electric field when it is accelerated through a potential difference (V). The formula for kinetic energy (KE) in terms of voltage is:

KE = eV

Here, e is the charge of the electron, approximately equal to 1.6 x 10-19 coulombs, and V is the potential difference in volts. In this case, the voltage difference is given as 40V.

Calculating the Kinetic Energy

Substituting the values into the formula:

KE = e × V = (1.6 x 10-19 C) × (40 V)

Now, let's calculate this:

KE = 1.6 x 10-19 C × 40 V = 6.4 x 10-18 joules

Converting Joules to Electron Volts

Since we want the kinetic energy in electron volts, we can use the conversion factor where 1 eV is equal to 1.6 x 10-19 joules. To convert joules to electron volts, we divide the energy in joules by the charge of the electron:

KE (in eV) = KE (in joules) / e

Substituting the values:

KE (in eV) = (6.4 x 10-18 J) / (1.6 x 10-19 J/eV)

Calculating this gives:

KE (in eV) = 40 eV

Summary of Findings

Thus, the kinetic energy of the electron, after being accelerated through a potential difference of 40V, is:

KE = 40 eV

This result aligns with our expectations, as the kinetic energy gained by the electron is directly proportional to the voltage through which it is accelerated. Therefore, in this experiment, the electron has a kinetic energy of 40 electron volts.

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