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In an experiment for measuring e/m, a cathode particle is passingthrough two deflecting plates maintained at voltage difference of 40V and separated by a distance of2cm.The cathode particle traveling at right angles to the field moves in a circularpath of radius 2m.Determine the KE of electron in eV.

Kevin Nash , 10 Years ago
Grade upto college level
anser 1 Answers
Yash Jain

Last Activity: 9 Years ago

See, in this case, the electrostatic force is providing the necessary centripetal acceleration.
So, mv2/r = eE = eV/d
Therefore, KE = ½*mv2 = ½*eVr/d 
Rest you can do it on your own (Be careful with unit conversions).

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