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If the two voltage measurements are V1= 150+_2%And V2= 100+_ 4% respectively. Then the maximum error in the sum of two voltage measurements is 1)+_2.4 % 2) +_2.6% 3)+_2.8%4)+_3.4%
error in V1 =150*2/100 = 3Verror in V2 = 100*4/100 = 4Verror in V1+V2 = 7*100/250 = 2.8%Hope it clears.
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