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Grade: 11
        
How to find maximum speed of car in this question plz tell me i am not able to solve this question 
3 months ago

Answers : (2)

Vikas TU
9517 Points
							
Dear student 
For the first leg of the journey, 
V = 0 + α  t1
So  V = α  t1 
for the second leg of journey of duration  t - t1 
0 = V - β (t - t1)
0 = α t1 - β t + β t1
t1 = β t / (α + β)
V =  αt1 = α β t / (α + β )
 
3 months ago
Rajat
213 Points
							
Take alpha to be a and beta to be b
Take time for acceleration be t
Time for deceleration = T-t
we know v= u+at
Initially car at rest,
So after acceleration,
v= 0+at
Velocity before deceleration is at,
And after deceleration is 0,
So, v= 0= at-b(T-t)
Thus, t= bT/(a+b)
So maximum velocity is,
at= abT/(a+b)
Please approve
 
3 months ago
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