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How to find maximum speed of car in this question plz tell me i am not able to solve this question
Dear student For the first leg of the journey, V = 0 + α t1So V = α t1 for the second leg of journey of duration t - t1 0 = V - β (t - t1)0 = α t1 - β t + β t1t1 = β t / (α + β)V = αt1 = α β t / (α + β )
Take alpha to be a and beta to be bTake time for acceleration be tTime for deceleration = T-twe know v= u+atInitially car at rest,So after acceleration,v= 0+atVelocity before deceleration is at,And after deceleration is 0,So, v= 0= at-b(T-t)Thus, t= bT/(a+b)So maximum velocity is,at= abT/(a+b)Please approve
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