How to find maximum speed of car in this question plz tell me i am not able to solve this question

Question

Vikas TU · Answer

Dear student

For the first leg of the journey,
V = 0 + α t1
So V = α t1

for the second leg of journey of duration t - t1
0 = V - β (t - t1)
0 = α t1 - β t + β t1

t1 = β t / (α + β)

V = αt1 = α β t / (α + β )

Rajat · Answer

Take alpha to be a and beta to be b Take time for acceleration be t Time for deceleration = T-t we know v= u+at Initially car at rest, So after acceleration, v= 0+at Velocity before deceleration is at, And after deceleration is 0, So, v= 0= at-b(T-t) Thus, t= bT/(a+b) So maximum velocity is, at= abT/(a+b) Please approve

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How to find maximum speed of car in this question plz tell me i am not able to solve this question

How to find maximum speed of car in this question plz tell me i am not able to solve this question

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