From the top of a tower 40 m, a ball is projected upwards with a speed of 20 m/s at an angle of 30° with the horizontal. if g=10m/s^2, after how long will the ball hit the ground?
Aditya Dhoble
8 Years agoGrade 11
1 Answer
Shailendra Kumar Sharma
8 Years ago
The velocity is 20m/s and the ball is thrown from a 40m tower
vertical component of velocity is vsin30 =10m/s
so 2nd law of newton s=ut+1/2(at2) -40 =20t - 5t2 Sp 5t2-20t-40=0 t2-4t-8=0