Frequency of a photon emitted due to transition of electron of a certain element from L to K shell is found to be 4.2 x 10 18 Hz. Using Moseley’s law, find the atomic number of the element, given that the Rydberg’s constant R = 1.1 x 10 7 m -1

Question

Navjyot Kalra · Answer

Hello Student,

Please find the answer to your question

According to Bohr’s model, the energy released during transition from n₂ to n₁ is given by

∆E = hv = Rhc (Z - b)² [1 / n²₁ – 1 / n²₂]

For transition from L shell to K shell

B = 1, n₂ = 2, n₁ = 1

∴ (Z - 1)² Rhc [1/1 – 1 / 4] = hv

On putting the value of R = 1.1 x 10⁷ m^-1 (given),

c = 3 x 10⁸ m/s, we get

Z = 42

Thanks
Navjot Kalra
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Frequency of a photon emitted due to transition of electron of a certain element from L to K shell is found to be 4.2 x 10 18 Hz. Using Moseley’s law, find the atomic number of the element, given that the Rydberg’s constant R = 1.1 x 10 7 m -1

Frequency of a photon emitted due to transition of electron of a certain element from L to K shell is found to be 4.2 x 10¹⁸ Hz. Using Moseley’s law, find the atomic number of the element, given that the Rydberg’s constant R = 1.1 x 10⁷ m^-1

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Frequency of a photon emitted due to transition of electron of a certain element from L to K shell is found to be 4.2 x 10 18 Hz. Using Moseley’s law, find the atomic number of the element, given that the Rydberg’s constant R = 1.1 x 10 7 m -1

Frequency of a photon emitted due to transition of electron of a certain element from L to K shell is found to be 4.2 x 1018 Hz. Using Moseley’s law, find the atomic number of the element, given that the Rydberg’s constant R = 1.1 x 107 m-1

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Frequency of a photon emitted due to transition of electron of a certain element from L to K shell is found to be 4.2 x 10¹⁸ Hz. Using Moseley’s law, find the atomic number of the element, given that the Rydberg’s constant R = 1.1 x 10⁷ m^-1