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Frequency of a photon emitted due to transition of electron of a certain element from L to K shell is found to be 4.2 x 10 18 Hz. Using Moseley’s law, find the atomic number of the element, given that the Rydberg’s constant R = 1.1 x 10 7 m -1

Frequency of a photon emitted due to transition of electron of a certain element from L to K shell is found to be 4.2 x 1018 Hz. Using Moseley’s law, find the atomic number of the element, given that the Rydberg’s constant R = 1.1 x 107 m-1

Grade:upto college level

1 Answers

Navjyot Kalra
askIITians Faculty 654 Points
8 years ago
Hello Student,
Please find the answer to your question
According to Bohr’s model, the energy released during transition from n2 to n1 is given by
∆E = hv = Rhc (Z - b)2 [1 / n21 – 1 / n22]
For transition from L shell to K shell
B = 1, n2 = 2, n1 = 1
∴ (Z - 1)2 Rhc [1/1 – 1 / 4] = hv
On putting the value of R = 1.1 x 107 m-1 (given),
c = 3 x 108 m/s, we get
Z = 42
Thanks
Navjot Kalra
askIITians Faculty

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