Express mass in terms of dimensions of velocity of light,Planck's constant and gravitational constant

Here, [c]=LT−1 
[G]=M−1L3T−2
[h]=M1L2T−1
Let m = cxGyhz

By substituting the dimensions of each quantity in both the sides,

M=(LT−1)x(M−1L3T−2)y(ML2T−1)z
M=[My+zLx+3y+2zTx−2y−z]
By equating the power of M, L, T in both the sides:

−y+z=1,x+3y+2z=0,−x−2y−z=0

By soling the above equation ,
We get, x=12,y=−12,andz=12

So, [m]=c12G−12h12