MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
Consider a system of two identical particals. One of the particles is at rest and the other has an acceleration f.the centre of mass has acceleration
 
10 months ago

Answers : (1)

Arun
22557 Points
							
Dear student
 
 
Let acm be the acceleration of the centre of mass of the two particles. Then,
                a_{cm}=\frac{m_{1}a_{1}+m_{2}a_{2}}{m_{1}+m_{2}}
Here since the particles are identical i.e, m1=m2=m(say)
          a_{cm}=\frac{m(a_{1}+a_{2})}{2m}=\frac{a_{1}+a_{2}}{2}               (1)
Taking a1=0(particle at rest) and a2= f, we get
        acm=f/2   
 
Regards
Arun (askIITians forum expert)
10 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details