# Consider a system of two identical particals. One of the particles is at rest and the other has an acceleration f.the centre of mass has acceleration

Arun
25757 Points
4 years ago
Dear student

Let acm be the acceleration of the centre of mass of the two particles. Then,
$a_{cm}=\frac{m_{1}a_{1}+m_{2}a_{2}}{m_{1}+m_{2}}$
Here since the particles are identical i.e, m1=m2=m(say)
$a_{cm}=\frac{m(a_{1}+a_{2})}{2m}=\frac{a_{1}+a_{2}}{2}$               (1)
Taking a1=0(particle at rest) and a2= f, we get
acm=f/2

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