Learn to Create a Robotic Device Using Arduino in the Free Webinar. Register Now
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Free webinar on Robotics (Block Chain) Learn to create a Robotic Device Using Arduino
30th Jan @ 5:00PM for Grade 1 to 10
calculate the wavelength in the visible spectrum (3500-7000)angstrom which coincide with the wavelength 6000 angstrom in 5th order? calculate the wavelength in the visible spectrum (3500-7000)angstrom which coincide with the wavelength 6000 angstrom in 5th order?
Since E=hvAnd c= v× lambdaThereforeE=hv = hc/ lambda = hc/6000 . --->1ZE= hv1 = hc/lambda ---->2From &. Zhc/6000. = hc/lambdaThereforelambda1 = 3000 A°
As learntThe energy (E) of a quantum of radiation -Where h is plank’s constant and is frequency- AND Speed of electromagnetic radiation -where frequency is (,pronounced as nu), wavelength is (λ) and velocity of light is(c) - We know, E= energy of a quantum of radiationh=plank's constant frequency of radiationand Now, Put in 2
As learnt
The energy (E) of a quantum of radiation -
Where h is plank’s constant and is frequency
-
AND
Speed of electromagnetic radiation -
where frequency is (,pronounced as nu), wavelength is (λ) and velocity of light is(c)
We know,
E= energy of a quantum of radiation
h=plank's constant
frequency of radiation
and
Now,
Put in 2
Dear studentThe above explanation is incorrect , Please do not follow..................................................Good Luck
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -