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calculate the ratio of the Kinetic energy required to be given to a satellite so that it escapes the gravitational field of earth to the Kinetic energy required to put the satellite in a circular orbit just about the free surface of earth.

Harsh Patel , 9 Years ago
Grade 11
anser 1 Answers
Askiitians Tutor Team

To determine the ratio of the kinetic energy needed for a satellite to escape Earth's gravitational field to the kinetic energy required for it to maintain a circular orbit just above the Earth's surface, we can break down the problem into manageable parts. Let's start by calculating both forms of kinetic energy.

Kinetic Energy for Escape Velocity

The kinetic energy (KE) required for a satellite to escape Earth's gravitational pull is related to the escape velocity. The escape velocity (v_escape) can be derived from the gravitational potential energy (U) and is given by the formula:

v_escape = √(2GM/R)

Here, G is the gravitational constant (approximately 6.674 × 10^-11 N(m/kg)^2), M is the mass of the Earth (about 5.972 × 10^24 kg), and R is the radius of the Earth (approximately 6.371 × 10^6 m).

Substituting these values, we find:

v_escape ≈ √(2 × 6.674 × 10^-11 × 5.972 × 10^24 / 6.371 × 10^6) ≈ 11,186 m/s

The kinetic energy required for escape can then be calculated using the formula:

KE_escape = 0.5 × m × v_escape²

Kinetic Energy for Circular Orbit

Next, we need to find the kinetic energy required for a satellite to maintain a circular orbit just above the Earth's surface. The orbital velocity (v_orbit) for a circular orbit is given by:

v_orbit = √(GM/R)

Using the same values for G, M, and R, we can calculate:

v_orbit ≈ √(6.674 × 10^-11 × 5.972 × 10^24 / 6.371 × 10^6) ≈ 7,900 m/s

The kinetic energy for this circular orbit is then:

KE_orbit = 0.5 × m × v_orbit²

Calculating the Ratio

Now that we have both kinetic energies, we can find the ratio of the kinetic energy required for escape to that required for a circular orbit:

Ratio = KE_escape / KE_orbit

Substituting the expressions for kinetic energy:

Ratio = (0.5 × m × v_escape²) / (0.5 × m × v_orbit²)

The mass (m) and the factor of 0.5 cancel out, leading to:

Ratio = v_escape² / v_orbit²

Now substituting the values we calculated:

Ratio = (11,186 m/s)² / (7,900 m/s)²

Calculating this gives:

Ratio ≈ (125,000,000) / (62,400,000) ≈ 2.008

Final Thoughts

The ratio of the kinetic energy required for a satellite to escape Earth's gravitational field to that required for it to maintain a circular orbit just above the Earth's surface is approximately 2.008. This means that the energy needed to escape is about twice that needed to stay in a low Earth orbit. This relationship highlights the significant energy difference between simply orbiting and breaking free from Earth's gravitational influence.

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