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Calculate the position of the planet 10^5 kg which is placed between the planets of 10^20kg and 10^24 kg which are placed at 6000km apart hence it will get zero gravitational force.(I have solved the question,I only want the working and Correct and complete answer)

Calculate the position of the planet 10^5 kg which is placed between the planets of 10^20kg and 10^24 kg which are placed at 6000km apart hence it will get zero gravitational force.(I have solved the question,I only want the working and Correct and complete answer) 

Grade:9

1 Answers

Vikas TU
14149 Points
one year ago
Hiii 
Gravitational force = GM1*M2/d2
Let us assume distance of 10^5 Kg particles from 10^20 Kg be x 
So gravitation force between them = G *10^25 /x2
Gravitational force between 10^5 and 10^24 kg mass will be = G* 10^29 /(6000-x)2
It is getting a zero gravitational force so, G*10^25 /x2 = G* 10^29 /(6000-x)2
(6000 – x)2  = 10^4 * x2
solve for x and apply quadratic equation formula , 
You will get X = 59.40 Km 

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