Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        Blocks A and B are connected by a bar of negligible weight. If mass of A and B are 170kg each and coefficient of limiting friction between blocks and plane are 0.2 and 0.4 for A and B. Calculate the force in the bar.`
one year ago

```							Is it 500 N along the plane. Approve if the answer is correct then I'll share the solution. ..................................................................
```
one year ago
```							We first calculate the net force downwards that is    m(A)gsin*theta* + m(B)gsin*theta*     Which is 1600NThen calculate total limiting friction That is  m(A)gcos*theta*(0.2) + m(B)gcos*theta*(0.4)  =  900 then calculate the net acceleration of the system        (1600-900)/170+170 = 700/340 m/s^2         After this draw FBD of block A and balance it By.        m(A)gsin*theta*   -   T(tension in bar)  = m(A)*acceleration of the system   Your answer would be    T= 150 NApprove if correct
```
one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Modern Physics

View all Questions »  ### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions