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An oscillator consists connected to with CA of a black of mass 5129 Spring when set into oscillation amplitude 347 cm, it is observed to repeat its motion every 6.484.5. final (a) the priod (b) the exquency, (c) the angular frequency ild) the force constanat (es maximum speed, and (f) the maximum force exerted on the block

ILYAS , 4 Years ago
Grade 13
anser 1 Answers
Askiitians Tutor Team

To analyze the motion of the oscillator you described, we can break down the problem into several parts. We have a block of mass 5129 grams (which we will convert to kilograms), a spring that allows for oscillation, and some given parameters like amplitude and period. Let’s tackle each part step by step.

Mass Conversion

First, we need to convert the mass from grams to kilograms since the standard unit of mass in physics is kilograms. The conversion is straightforward:

  • Mass (m) = 5129 grams = 5.129 kg

Understanding the Period

The period (T) of an oscillator is the time it takes to complete one full cycle of motion. You mentioned the period as 6.4845 seconds. This value is crucial for calculating frequency and angular frequency.

Calculating Frequency

Frequency (f) is the number of cycles per second and is the reciprocal of the period:

  • f = 1/T
  • f = 1/6.4845 ≈ 0.1545 Hz

Finding Angular Frequency

The angular frequency (ω) relates to frequency and is calculated using the formula:

  • ω = 2πf
  • ω = 2π(0.1545) ≈ 0.970 rad/s

Force Constant of the Spring

The force constant (k) of the spring can be determined using the formula that relates mass, angular frequency, and spring constant:

  • ω = √(k/m)
  • Rearranging gives us k = ω²m
  • k = (0.970)²(5.129) ≈ 4.81 N/m

Maximum Speed of the Block

The maximum speed (v_max) of the block in simple harmonic motion occurs at the equilibrium position and can be calculated using the formula:

  • v_max = ωA
  • Where A is the amplitude in meters (347 cm = 3.47 m)
  • v_max = 0.970 * 3.47 ≈ 3.37 m/s

Maximum Force Exerted on the Block

The maximum force (F_max) exerted by the spring when the block is at maximum displacement can be calculated using Hooke's Law:

  • F_max = kA
  • F_max = 4.81 * 3.47 ≈ 16.67 N

Summary of Results

To summarize, here are the results of our calculations:

  • Period (T): 6.4845 seconds
  • Frequency (f): 0.1545 Hz
  • Angular Frequency (ω): 0.970 rad/s
  • Force Constant (k): 4.81 N/m
  • Maximum Speed (v_max): 3.37 m/s
  • Maximum Force (F_max): 16.67 N

These calculations provide a comprehensive understanding of the dynamics of the oscillator system you described. If you have any further questions or need clarification on any of the steps, feel free to ask!

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