An object is displaced from position vector r1 = (2i + 3j)m to r2 = (4i + 6j)m under a force F = (3x2i + 2yj)N. Find the work down by this force.

NOTE : '[' is the integration symbol W.D = 2[4 3x2 dx + 3[6 2y dy = x3 2|4 + y2 3|6 = 64 – 8 + 36 – 9 = 56 + 27 = 83J

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An object is displaced from position vector r₁ = (2i + 3j)m to r₂ = (4i + 6j)m under a force F = (3x²i + 2yj)N. Find the work down by this force.

AkashGanga , 7 Years ago

Grade 12th pass

2 Answers

Sujit Kumar

Last Activity: 7 Years ago

NOTE : '[' is the integration symbol

W.D = ₂[⁴ 3x²dx + ₃[⁶ 2y dy

= x³₂|⁴+ y² ₃|⁶= 64 – 8 + 36 – 9 = 56 + 27 = 83J

Approved

Khimraj

Last Activity: 7 Years ago

Work done = $\int_{x1}^{x2}F_{x}dx + \int_{y1}^{y2}F_{y}dy$ = $\int_{2}^{4}3x^{2}dx + \int_{3}^{6}2ydy$ = 83J

Hope it clears.

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Modern Physics> An object is displaced from position vect...

An object is displaced from position vector r1 = (2i + 3j)m to r2 = (4i + 6j)m under a force F = (3x2i + 2yj)N. Find the work down by this force.

AkashGanga , 7 Years ago

Sujit Kumar

Khimraj

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