Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

An npn transistor operates as a common emitter amplifier with a power gain of 60dB .The input circuit resistance is 100 ohm and the output load resistance is 10000 ohm. The common emitter current gain is?

An npn transistor operates as a common emitter amplifier with a power gain of 60dB .The input circuit resistance is 100 ohm and the output load resistance is 10000 ohm. The common emitter current gain is?

Grade:12

1 Answers

Mayank
368 Points
one year ago
we know that  power gain = voltage gain * current gain  so now current gain =\beta  and voltage gain = (\beta* R)/r where R =output load resistance and r=input load resistance so now the power gain =(\beta*\beta*R)/r so  now numerically we have 
 
   60=(\beta*\beta*10000)/100 so from here we get  \beta*\beta=0.6  and hence \beta=0.77459

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free