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Grade upto college level Modern Physics

An electron, in a hydrogen-hydrogen-like atom, is in an excited state. It has a total energy of – 3.4 eV. Calculate (i) the kinetic energy and (ii) the de Broglie wavelength of the electron

Amit Saxena

12 Years agoGrade upto college level

1 Answer

Navjyot Kalra

12 Years ago

Hello Student,

Please find the answer to your question

(i) E_n = - 3.4 eV

The kinetic energy is equal to the magnitude of total energy in this case.

∴ K.E. = + 3.4 eV

(ii) The de Broglie wavelength of electron

Λ = h / √ 2mK = 6.64 x 10^-34 / √ 2 x 9.1 x 10^-31 x 3.4 x 1.6 x 10^-19 eV

= 0.66 x 10^-9 m

Thanks
Navjot Kalra
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