Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

AIPMT 2014 Q41 Please provide a detailed solution.......

AIPMT 2014 Q41 Please provide a detailed solution.......

Grade:12th pass

1 Answers

Umakant biswal
5359 Points
4 years ago
energy of a photon = E= hc / lambda = 12.75 ev 
the enrgy is equal to energy gap between n = 1 (-13.6 ) and n = 4 (-0.85 ) so, by this energy the electron will exite from n= 1 to n= 4 . , 
when the electron will fall back , the no of spectral lines emitted = n (n-1 ) / 2 
4(4-1) / 2= 6 
its the answer , 
its acc to the question paper that i have , but dnt know its your ques or not as u have not attached any ques . 
ALL THE BEST ..,

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free