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A uniform rod AB of length 7m is undergoing combined rotational and translational
motion such that at some instant of time,velocities of its end points A and centre
C are both perpendiculaar to the rod and opposite in direction, having magnitudes
11m/s and 3m/s respectively

jakira , 9 Years ago
Grade 12
anser 1 Answers
Askiitians Tutor Team

Last Activity: 5 Months ago

To analyze the motion of the uniform rod AB, we need to consider both its translational and rotational aspects. The rod is 7 meters long, and at a specific moment, the velocities of its endpoints A and C are perpendicular to the rod and directed oppositely. Let's break this down step by step to understand the dynamics involved.

Understanding the Motion of the Rod

The rod is undergoing combined motion, which means it is both translating and rotating. The key points to focus on are:

  • Velocity of point A (end of the rod) = 11 m/s (in one direction)
  • Velocity of point C (center of the rod) = 3 m/s (in the opposite direction)

Translational Motion

The translational motion of the rod can be described by the velocity of its center of mass (C). Since point C is the midpoint of the rod, its velocity represents the overall translational motion of the rod. Here, the center C has a velocity of 3 m/s. This means that the entire rod is moving in the direction of point C's velocity.

Rotational Motion

Next, we need to consider the rotational motion about the center of mass. The rod is rotating about its center C, and we can determine the angular velocity (ω) using the relationship between linear velocity and angular velocity:

For a point on the rod, the linear velocity (v) is related to the angular velocity (ω) by the equation:

v = ω * r

Where r is the distance from the center of mass to the point in question. For point A, which is 3.5 meters away from C (half the length of the rod), we can express the velocity of point A as:

11 m/s = ω * 3.5 m

Calculating Angular Velocity

Now, we can solve for ω:

ω = 11 m/s / 3.5 m = 3.14 rad/s

Direction of Motion

Since the velocities of points A and C are opposite, we can infer that the rod is rotating in a clockwise direction about point C. This means that while point A is moving to the left at 11 m/s, point C is moving to the right at 3 m/s.

Summary of Findings

In summary, the uniform rod AB is experiencing both translational and rotational motion. The center of mass C moves at 3 m/s, while point A moves at 11 m/s in the opposite direction. The angular velocity of the rod is approximately 3.14 rad/s, indicating a clockwise rotation. Understanding these dynamics helps us analyze how objects behave under combined motion, which is crucial in fields like physics and engineering.

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