A triode has plate characteristics in the form of

Question

A triode has plate characteristics in the form of parallel lines in the region of our interest. At a grid voltage of – I volt the anode current – I (In milli amperes ) is given in terms of plate voltage V ( in volts) by the algebraic relation.I = 0.125 V – 7.5For grid voltage of – 3 volts, the current at anode voltage of 300 volts is 5 milliampere. Determine the plate resistance (rp), transconductance (gm) and the amplification factor (μ) for the triode.

Kevin Nash · Accepted Answer

Hello Student,

Please find the answer to your question

I = 0.125 V – 7.5

⇒ dl = 0.125 dV or dV / dl = 1 / 0.125 = 8

We know that plate resistance, r_p = dV / dl = 8mΩ

The transconductance , g_m = [dl / dV_g] v = constt

At V_g = - 1 volt , V = 300 volt, the plate current

I = [0.125 x 300 – 7.5] mA = 30 mA

Also it is given that V_g = - 3V, V = 300 V and I = 5mA

∴ g_m = [30 – 5 / - 1 – (- 3)] = 25 / 2 x 10^-3= 12.5 x 10^-3 s

The characteristics are given in the form of parallel lines.

Amplification factor

= r_p g_m = 8 x 10³ x 12. 5 x 10^-3 = 100

Thanks
Kevin Nash
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