A thin lens has focal length f, and its aperture has diameter d. It forms an image of intensity I. Now, the central part of the aperture up to diameter d/2 is blocked by an opaque paper The image intensity will change toChoose the correct answer:a. f/2 and I/2b. f and I/4c. 3f /4 and I/2d. f and 3I/4

Dear Student,
Please find below the solution to your problem.

Focal length will remains same.
Intensity is directly proportional to the area of the aperture of the lens receiving the light.
Total area of the aperture is,
A = pi * d²/4
Remaining area after covering,
A' = pi *(d²/4 - d²/16) = 3 * pi* d²/16
I/I' = A/A' = 4/3
I' = 3 I/4

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