A stone is dropped from rest from top of a cliff

Question

A stone is dropped from rest from top of a cliffA second stone is thrown vertically down with a velocity of30m/s two seconds later. At what distance from the top of the cliff do they meet?

Arun · Accepted Answer

Dear student The to a stone's meet at a distance S from top of Cliff tseconds after first stone is dropped.For 1st stone S = 1/2 gt² For 2nd stone S = u( t -2 ) + 1/2 g(t-2)²now equate the both distance 1/2 gt² = ut – 2u + 1/2 gt² – 2gt + 2g0 = ( u - 2g) t - 2(u- g )t = 2( u - g ) /u - 2g = 2(30 - 10 ) /30 - 20 = 4 sec t = 4 second distances S at which they meet = 1/2 * gt² = 1/2 * 10 * 16= 80 m from top of CliffRegardsArun (askIITians forum expert)

Modern Physics> A stone is dropped from rest from top of ...

A stone is dropped from rest from top of a cliffA second stone is thrown vertically down with a velocity of30m/s two seconds later. At what distance from the top of the cliff do they meet?

Manjeet , 6 Years ago

Arun

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Modern Physics> A stone is dropped from rest from top of ...

A stone is dropped from rest from top of a cliffA second stone is thrown vertically down with a velocity of30m/s two seconds later. At what distance from the top of the cliff do they meet?

Manjeet , 6 Years ago

Arun

Provide a better Answer & Earn Cool Goodies

LIVE ONLINE CLASSES

Ask a Doubt

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