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Grade 12th passModern Physics

A spacecraft approaching the earth at 0.6c transmit data at the rate of 40 pulses/s. At what rate are they received? (3)

A.

B.

C.

D.

E.

Profile image of godfrey Thobejane
4 Years agoGrade 12th pass
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1 Answer

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer11 Months ago

To determine the rate at which the pulses are received on Earth from a spacecraft approaching at 0.6 times the speed of light (0.6c), we need to consider the effects of relativistic Doppler shift. This phenomenon occurs because the frequency of waves changes depending on the relative motion of the source and the observer.

Understanding the Doppler Effect

The relativistic Doppler effect can be described using the formula:

f' = f √((1 + β) / (1 - β))

where:

  • f' is the observed frequency (rate of pulses received).
  • f is the emitted frequency (rate of pulses transmitted).
  • β is the ratio of the velocity of the source to the speed of light (v/c).

Calculating the Parameters

In this scenario:

  • The emitted frequency, f, is 40 pulses/s.
  • The speed of the spacecraft, v, is 0.6c, which gives us β = 0.6.

Applying the Formula

Now, we can substitute these values into the Doppler effect formula:

f' = 40 √((1 + 0.6) / (1 - 0.6))

Calculating the terms inside the square root:

  • 1 + 0.6 = 1.6
  • 1 - 0.6 = 0.4

This gives us:

f' = 40 √(1.6 / 0.4)

Now, simplifying the fraction:

1.6 / 0.4 = 4

Thus, we have:

f' = 40 √4

Since the square root of 4 is 2, we find:

f' = 40 * 2 = 80 pulses/s

Final Result

The rate at which the pulses are received on Earth is therefore 80 pulses/s. This corresponds to option C in the choices provided.