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a rubber ball of mass 50 g falls from a height of 1 m and rebounds to a height of 0.5 m. find the change in momentum of the ball
Initial velocity of ball at A = 0. Final velocity of ball at B = v s = 1 m As v2 - u2 = 2as v2 - 02 = 2 x 9.8 x 1 or v = ?19.6 m/s Let u' be the velocity of rebound of the ball. s' = 50 cm = 0.5 m, g = - 9.8 m/s2 Final velocity at C = v' = 0 As v2 - u2 = 2as Therefore 02 - (u')2 = 2 x (-9.8) x 0.5 or u' = ?9.8 m/s Now, Impulse = Change in momentum = mv - (-mu') = mv + mu' = m(v+ u) = 50/1000 (?19.6 + ?9.8) = 1/20 (4.427 + 3.130) = 0.378 Ns
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