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A rope is used to pull a 2.89-kg bucket of water out of a deep well. What is the acceleration of the bucket when the tension in the rope is 30.2 N?

Vikas TU
14149 Points
4 years ago
T – mg = ma
a = (T-mg)/m
= (30.2 – 28.9)/2.89
= 0.5 m/s^2 approx. would be the accln. of the rope required to pull the 2.89 kg bucket of water.
Mars
11 Points
3 years ago
$\sum F= T - W ma = T - mg 2.89(a) = 30.2 - 2.89(9.81) a = 0.64 m/s$