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A resistor in a circuit dissipates energy at a rate of 1 W. If the voltage across the resistor is doubled, what will be the new rate of energy dissipation? please give process

theja , 12 Years ago
Grade 9
anser 3 Answers
Arpit Kumar
From Ohm`s law we have V=IR This means V is directly proportional to R,hence if V is doubled R also gets doubled.This means rate of dissipation of energy also gets doubled,hence new rate=2 W
Last Activity: 12 Years ago
Saif
New rate won`t be =2. That would be wrong. In this case we need to use the relationship of energy, voltage and resistance which is, P=v²/RAccording to this relationship P~V² so if you double the voltage you would get (2)²=4 times the energy dissipation. :)
Last Activity: 8 Years ago
Ahmed Mabrouk
We can’t use the rule P= VI as all of themare variables so the best rule will be P= v2/R so the right answer is 4
Last Activity: 6 Years ago
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