MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 9
        A resistor in a circuit dissipates energy at a
rate of 1 W. If the voltage across the resistor
is doubled, what will be the new rate of energy
dissipation?

please give process
6 years ago

Answers : (3)

Arpit Kumar
31 Points
							From Ohm`s law we have V=IR
This means V is directly proportional to R,hence if V is doubled R also gets doubled.This means rate of dissipation of energy also gets doubled,hence new rate=2 W
						
6 years ago
Saif
11 Points
							New rate won`t be =2. That would be wrong. In this case we need to use the relationship of energy, voltage and resistance which is, P=v²/RAccording to this relationship P~V² so if you double the voltage you would get (2)²=4 times the energy dissipation. :)
						
3 years ago
Ahmed Mabrouk
13 Points
							
We can’t use the rule P= VI as all of themare variables so the best rule will be P= v2/R so the right answer is 4
2 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details