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A resistor in a circuit dissipates energy at a rate of 1 W. If the voltage across the resistor is doubled, what will be the new rate of energy dissipation? please give process

A resistor in a circuit dissipates energy at a
rate of 1 W. If the voltage across the resistor
is doubled, what will be the new rate of energy
dissipation?

please give process

Grade:9

3 Answers

Arpit Kumar
31 Points
7 years ago
From Ohm`s law we have V=IR This means V is directly proportional to R,hence if V is doubled R also gets doubled.This means rate of dissipation of energy also gets doubled,hence new rate=2 W
Saif
11 Points
4 years ago
New rate won`t be =2. That would be wrong. In this case we need to use the relationship of energy, voltage and resistance which is, P=v²/RAccording to this relationship P~V² so if you double the voltage you would get (2)²=4 times the energy dissipation. :)
Ahmed Mabrouk
13 Points
one year ago
We can’t use the rule P= VI as all of themare variables so the best rule will be P= v2/R so the right answer is 4

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