Modern Physics> A radioactive metal decay by simaltenuous...

A radioactive metal decay by simaltenuous emission of two particles with two half live 1620 and 810 respectively. the time in year after one-forth of substances remain?1080234032404860

akash , 7 Years ago

Grade 12th pass

1 Answers

Khimraj

Last Activity: 7 Years ago

Let the two particle are a and b. and as decay constant $\lambda$ are given by

$\lambda$ _a = ln2/(t_1/2)_a = ln2/1620

$\lambda$ _b = ln2/(t_1/2)_b = ln2/810

Total decay constant $\lambda$ = $\lambda$ _a+ $\lambda$ _b

$\lambda$ = ln2/1620 + ln2/810 = 3*ln2/1620

when (1/4)^th of metal remains

N₀/4 = N₀e^-λt

λt = ln4

t = 2ln2/λ = 2*ln2/λ = (2/3)*1620 = 1080 years.

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Modern Physics> A radioactive metal decay by simaltenuous...

A radioactive metal decay by simaltenuous emission of two particles with two half live 1620 and 810 respectively. the time in year after one-forth of substances remain?1080234032404860

akash , 7 Years ago

Khimraj

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