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A projectile is launched with an initial velocity of 1.5km/s^-1 at an angle theta the target is located at a distance of 3000m and on the same level. The projectile strikes the target after 4.0sa.determine the horizontal velocity of the projectileb.calculate the value of theta

Ravi
15 Points
8 months ago
range=u2sin2$\theta$/2g
range=3000
u=1.5km/s is equal to 1500m/s
by above formula you will get $\theta$
then ucos$\theta$ is the horizontal velocity