0

Guest

Courses New

a point source of light is placed at the center of curvature of a hemispherical surface. radius r&inner surface is totally reflecting.find force on the hemisphere due 2 lightfalling on it if source emits power w MY APPROACH ENERGY EMITED by source in 4pie solid angle per sec = W for hemisphere solid angle=2pie so, energy falling/sec on hemisphere =(w/4pie)*(2pie)=w/2 momentum=e/c=w/2c as the surface is reflecting so total momentumchange=2*(w/2c)=w/c HOWEVER THE ANSER IS GIVEN W/2C IN H.C.VERMA2 PG NO.360 QN NO.6 TELL HOW


a point source of light is placed at the center of curvature of a hemispherical surface. radius r&inner surface is totally reflecting.find force on the hemisphere due 2 lightfalling on it if source emits power w
 MY APPROACH
ENERGY EMITED by source in 4pie solid angle per sec = W
for hemisphere solid angle=2pie
so, energy falling/sec on hemisphere =(w/4pie)*(2pie)=w/2
momentum=e/c=w/2c
as the surface is reflecting so total momentumchange=2*(w/2c)=w/c
HOWEVER THE ANSER IS GIVEN W/2C IN H.C.VERMA2 PG NO.360 QN NO.6
TELL HOW


Grade:10

0 Answers

No Answer Yet!

Other Related Questions on Modern Physics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More