Grade 11Modern Physics

a planet of mass 1/10 of the earth and radius of 1/3 of the earth. If a person can throw a stone on earth surface to a height of 90m, he will able to throw the stone on that planet to a height

Digvijay Patel

9 Years agoGrade 11

2 Answers

Vikas TU

9 Years ago

g constant on earth that is,

g = GM/R

g constat at the planet that is,

g’ = 3GM/10R

relation b/w them is:

g’ = 3g/10

Now energy would remain contant.

Hence,

mg*90 = m*3g*h/10

we get,

h = 300 m.

Namisha

7 Years ago

We have;

g=Gm/R^2

'g' on the other planet using the above formula is

g=Gm/10(R/3)^2

=9Gm/10R^2

Which is...g of other planet is equals to 9/10 times of that of the g of Earth.

So; as the energy would remain constant

Use mgh..

m*g*90=m*9g*h/10

So from here h=100m

So h=100m is the height at which we will be able to throw the stone on that planet

:-)

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a planet of mass 1/10 of the earth and radius of 1/3 of the earth. If a person can throw a stone on earth surface to a height of 90m, he will able to throw the stone on that planet to a height

Digvijay Patel

2 Answers

Vikas TU

Namisha

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