Modern Physics> A particle moving with uniform accelerati...

A particle moving with uniform acceleration in a straight line covers a distance of 3m in the 8th second and the 5m in the 16th second of its motion .What is the displacement of the particle from the beginning of the 6th sec to the end of 15th sec?

Rupesh patil , 8 Years ago

Grade 11

1 Answers

Vikas TU

Last Activity: 8 Years ago

Dear Student,

From the Newton’s third law of eqn.

V²- u²/ 2a = 3
=>6a= v²-u²

v=x+8a
u=x+7a

6a= 15a²+2ax
=>6=15a+2x

10a=(x+16a)²-(x+7a)²
=>10=31a+2x

10-6=(31a+2x)-(15a+2x)
=>4=16a
=>a=1/4 m/s²

Velocity at the start of 6^th second = x+5a
=19/8 m/s

15/4+2x=6
=>x=9/8

Displacement = 19/8x11 + ½ x ¼ x 121
=41.25m.

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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Modern Physics> A particle moving with uniform accelerati...

A particle moving with uniform acceleration in a straight line covers a distance of 3m in the 8th second and the 5m in the 16th second of its motion .What is the displacement of the particle from the beginning of the 6th sec to the end of 15th sec?

Rupesh patil , 8 Years ago

Vikas TU

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