Vikas TU
Last Activity: 8 Years ago
Dear Student,
From the Newton’s third law of eqn.
V2 - u2 / 2a = 3
=>6a= v2-u2
v=x+8a
u=x+7a
6a= 15a
2+2ax
=>6=15a+2x
10a=(x+16a)
2-(x+7a)
2=>10=31a+2x
10-6=(31a+2x)-(15a+2x)
=>4=16a
=>a=1/4 m/s
2Velocity at the start of 6
th second = x+5a
=19/8 m/s
15/4+2x=6
=>x=9/8
Displacement = 19/8x11 + ½ x ¼ x 121
=41.25m.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)