A particle moving with uniform acceleration in a straight line covers a distance of 3m in the 8th second and the 5m in the 16th second of its motion .What is the displacement of the particle from the beginning of the 6th sec to the end of 15th sec?

Question

Vikas TU · Answer

Dear Student,

From the Newton’s third law of eqn.

V²- u²/ 2a = 3
=>6a= v²-u²

v=x+8a
u=x+7a

6a= 15a²+2ax
=>6=15a+2x

10a=(x+16a)²-(x+7a)²
=>10=31a+2x

10-6=(31a+2x)-(15a+2x)
=>4=16a
=>a=1/4 m/s²

Velocity at the start of 6^th second = x+5a
=19/8 m/s

15/4+2x=6
=>x=9/8

Displacement = 19/8x11 + ½ x ¼ x 121
=41.25m.

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

A particle moving with uniform acceleration in a straight line covers a distance of 3m in the 8th second and the 5m in the 16th second of its motion .What is the displacement of the particle from the beginning of the 6th sec to the end of 15th sec?

A particle moving with uniform acceleration in a straight line covers a distance of 3m in the 8th second and the 5m in the 16th second of its motion .What is the displacement of the particle from the beginning of the 6th sec to the end of 15th sec?

1 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Modern Physics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship