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a particle moving with uniform acceleration has its final velocity [v=(150+8x)1/2] m/s where x is the distance travelled by the body. Then the acceleration is
​1) + 4 m/s2
​2) – 4 m/s2
​3) + 8 m/s2
​4) – 8 m/s2
Answer: + 4 m/s2

ANMOL , 7 Years ago
Grade 11
anser 1 Answers
Eshan

Last Activity: 7 Years ago

v=\sqrt{150+8x} \implies v^2=150+8x

This can be compared to equation of motion for constant acceleration,v^2=u^2+2ax

Hencea=+4m/s^2

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