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# A particle moves in a circular path of radius 5cm in a plane perpendicular to the principle axis of a convex mirror with radius of curvature 20cm.The object is 15cm in front of the mirror. Calculate the radius of the circular path of the image

Ravi
15 Points
one month ago
given ,
the particle is rotating circle motion in plane perpendicular to principal axis at a distance of 15cm
means particle is at a constant height of 5cm
in convex mirror:
$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}$
f=+10  , u= -15
by using above formula v=6
height of object=5cm
height of image
$\Rightarrow \tfrac{h(image)}{h(object)}= -\frac{v}{u}$
by using above formula:
h(image)=2
this height of image is the radius of circular path of image=2