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A particle is projected vertically upward with initial velocity 25m/s.during third second of its motion what distance it will travel

A particle is projected vertically upward with initial velocity 25m/s.during third second of its motion what distance it will travel

Grade:11

1 Answers

Kuntal Paul
42 Points
3 years ago
If the distance covered in n th second is d, then d= u+(1/2)a(2n+1),where u is initial velocity and a is acceleration. Here a is negative and it`s value is 10 m/s^2. So the answer will be -10 m. The negative sign denotes that the particle will travel 10 m vertically downwards in the third second after attaining its maximum height.

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