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A monochromatic light incident on metal "A" having threshold frequency"nu-not". It emits photo electrons of maximum KE "K". Now incident frequency Is made three times and fall on metal B having threshold frequency 2 nu-not. What will maximum KE of photo electrons emitted by metal "B"?(Answer to this question is given to be-- 3K+h nu-not) Please solve it

A monochromatic light incident on metal "A" having threshold frequency"nu-not". It emits photo electrons of maximum KE "K". Now incident frequency Is made three times and fall on metal B having threshold frequency 2 nu-not. What will maximum KE of photo electrons emitted by metal "B"?(Answer to this question is given to be-- 3K+h nu-not) Please solve it

Grade:11

1 Answers

Norman Manchu
151 Points
3 years ago
I got it and sorry for the last similar question I didn`t figure out this expression as the answer|I`d be using v for incident frequency and v° for threshold one|For metal A;hv=hv°+KK=hv-hv°Multiply throughout by 33K=3hv-3hv°------(1)For metal B;3hv=2hv°+KE(we`re required to find this)KE=3hv-2hv°-----(2)Equation (1)-(2)(Subtraction)3K-KE=3hv-3hv°-3hv+2hv°=-hv°Therefore;KE=3K+hv°

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