A fireman of mass 80 kg slides down a pole during a rescue mission . The force of friction is constant at 720 N .Find the acceleration of the man.(g=10 m per second square )..

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Arun · Answer

Dear Deepak Resultant force = 800 – 720 = 80N now 80 = m * a 80 = 80 * a a = 1 m/sec^2 Regards Arun (askIITians forum expert)

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A fireman of mass 80 kg slides down a pole during a rescue mission . The force of friction is constant at 720 N .Find the acceleration of the man.(g=10 m per second square )..

A fireman of mass 80 kg slides down a pole during a rescue mission . The force of friction is constant at 720 N .Find the acceleration of the man.(g=10 m per second square )..

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A fireman of mass 80 kg slides down a pole during a rescue mission . The force of friction is constant at 720 N .Find the acceleration of the man.(g=10 m per second square )..

A fireman of mass 80 kg slides down a pole during a rescue mission . The force of friction is constant at 720 N .Find the acceleration of the man.(g=10 m per second square )..

1 Answers

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