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Grade: 11

                        

A density bottle contains 104.5 degree centigrade of a liquid at 34 degree centigrade on heating it to 100 degree centigrade the mass of the liquid expelled is 4.5gms.Then find the coefficient of apparent expansion of liquid.

6 years ago

Answers : (3)

Nirmal Singh.
askIITians Faculty
44 Points
							
Let the density of the liquid in the density bottle be `d`
Then volume of the liquid at 34degree centigrade V1=md=104.5d
volume of the liquid expelled when it is heated to 100degree centigrade(V2-V1)=4.5d
Coefficient of apparent expansion of liquid=[V2-V1]/[V1*(100-34)]
=[4.5d]/[104.5d*66]
=0.000652458
Regards,
Nirmal Singh
Askiitians faculty
=0.000652458
=0.000652458
6 years ago
sivakrishna
37 Points
							let the density of the liquid in the bottle be d.
Given ,
          m1=104.5gms
          t1=34 degree centigrade
          m2=m1+4.5
               =104.5+4.5
              =109gms
           t2=100degree centigrade
we know that the coefficient of apparent expansion=(V2-V1)/V1(t2-t1)         d=m/V>v=m/d
                                                                                 = (m2/d-m1/d)m1/d*(100-34)
                                                                                 =(109/d-104.5/d)/104.5/d*(66)
                                                                                 =(4.5/d)/6897/d
                                                                                 =4.5/6897
                                                                                =0.000652457
                                                                                =0.0007/degree centigrade
						
6 years ago
Vyshnavi
20 Points
							Let density of liquid in the liquid bottle be `d`
Then volume of liquid at 34 degree centigrade v1=md=104.5d
Volume of liquid expelled when it is heated to 100 degree centigrade(V2-V1)=4.5d
Coefficient of apparent expansion of liquid =[V2-V1]/[V1*(100-34)]
=[4.5d]/[104.5d*66]
=0.000652457
=0.0007/degree centigrade
						
6 years ago
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