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A density bottle contains 104.5 degree centigrade of a liquid at 34 degree centigrade on heating it to 100 degree centigrade the mass of the liquid expelled is 4.5gms.Then find the coefficient of apparent expansion of liquid.

```
6 years ago

```							Let the density of the liquid in the density bottle be `d`Then volume of the liquid at 34degree centigrade V1=md=104.5dvolume of the liquid expelled when it is heated to 100degree centigrade(V2-V1)=4.5dCoefficient of apparent expansion of liquid=[V2-V1]/[V1*(100-34)]=[4.5d]/[104.5d*66]=0.000652458Regards,Nirmal SinghAskiitians faculty=0.000652458
=0.000652458

```
6 years ago
```							let the density of the liquid in the bottle be d.
Given ,
m1=104.5gms
m2=m1+4.5
=104.5+4.5
=109gms
we know that the coefficient of apparent expansion=(V2-V1)/V1(t2-t1)         d=m/V>v=m/d
= (m2/d-m1/d)m1/d*(100-34)
=(109/d-104.5/d)/104.5/d*(66)
=(4.5/d)/6897/d
=4.5/6897
=0.000652457
```
6 years ago
```							Let density of liquid in the liquid bottle be `d`
Then volume of liquid at 34 degree centigrade v1=md=104.5d
Volume of liquid expelled when it is heated to 100 degree centigrade(V2-V1)=4.5d
Coefficient of apparent expansion of liquid =[V2-V1]/[V1*(100-34)]
=[4.5d]/[104.5d*66]
=0.000652457
```
6 years ago
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