A cricket ball of mass 100 gram is moving with a speed of 25 metre per second and brought to rest in 0.025 seconds find the average force apply and impulse

Question

Arun · Answer

mass of the ball (m) =100g or 0.1kg
initial velocity (u) =25 m/s
time (t) = 0.025sec.
final velocity (v) = 0

Initial momentum = mu

= 0.1kg*25m/s
= 2.5 kgm/s

Final momentum = mv (which is equal to 0, since v is zero)
Change in momentum = mv-mu

= 0 - 2.5 = -2.5 kgm/s

Average force = Change in momentum / time

= -2.5 kgms-1 /0.025s
= -100 kgm/s2
= -100 N

The negative sign actually shows that the force was applied oppasite to the direction of the motion of the ball. So, the average force applied by the player will be 100 N.

anjace · Answer

impulse=f*t f=ma acceleration can be calculated by 1 st lw of motion a=-1000 avg force=impulse/time which is equal to -100 n

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A cricket ball of mass 100 gram is moving with a speed of 25 metre per second and brought to rest in 0.025 seconds find the average force apply and impulse

A cricket ball of mass 100 gram is moving with a speed of 25 metre per second and brought to rest in 0.025 seconds find the average force apply and impulse

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