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A cricket ball of mass 100 gram is moving with a speed of 25 metre per second and brought to rest in 0.025 seconds find the average force apply and impulse
mass of the ball (m) =100g or 0.1kginitial velocity (u) =25 m/stime (t) = 0.025sec.final velocity (v) = 0 Initial momentum = mu = 0.1kg*25m/s = 2.5 kgm/s Final momentum = mv (which is equal to 0, since v is zero) Change in momentum = mv-mu = 0 - 2.5 = -2.5 kgm/s Average force = Change in momentum / time = -2.5 kgms-1 /0.025s = -100 kgm/s2 = -100 NThe negative sign actually shows that the force was applied oppasite to the direction of the motion of the ball. So, the average force applied by the player will be 100 N.
impulse=f*tf=maacceleration can be calculated by 1st lw of motiona=-1000avg force=impulse/time which is equal to -100 n
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