# A converging lens a focal length of 30 cm.Rays from a 2.0 cm high fliament that pass through the lens form a virtual image at a distance of 50 cm from the lens.where is the fliament located?what is the height of the image?

Arun Kumar IIT Delhi
8 years ago
$1/f=1/d_{o}+1/d_{i} \\=>1/30=1/50+1/d_{o} \\=>d_{o}=75$

where d is distance
$M=h_{i}/h_{o}=-d_{i}/d_{o} \\=>|h_{i}|=50*2/75=4/3cm$

Arun Kumar
IIT Delhi