Modern Physics> A certain ruby laser emits 1.00 Joule pul...

A certain ruby laser emits 1.00 Joule pulse of light whose wavelength is 694 nm. What is the minimum number of Cr3+ ions in ruby?

Prem Barak , 7 Years ago

Grade 12th pass

1 Answers

Khimraj

h = 6.63*10^-34 c = 3*10⁸ $\lambda$ = 694*10^-9

The energy of a 694 nm photon is

E = hc/ $\lambda$ = 2.866*10^-19 J

In each pulse of light, there are

n = 1/E photons, because 1 joule per pulse divided by joules per photon gives photons per pulse.

n = 3.489*10¹⁸ photons

There must be at least that many chromium 3+ ions in the crystal.

Hope it clears........................

Last Activity: 7 Years ago

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Modern Physics> A certain ruby laser emits 1.00 Joule pul...

A certain ruby laser emits 1.00 Joule pulse of light whose wavelength is 694 nm. What is the minimum number of Cr3+ ions in ruby?

Prem Barak , 7 Years ago

Khimraj

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