To determine the acceleration of the Boeing 707 and the length of the runway required for it to become airborne, we can break the problem down into a few logical steps. First, we need to calculate the total thrust produced by the engines, then use Newton's second law to find the acceleration, and finally, apply kinematic equations to find the runway length needed to reach the takeoff speed.
Calculating Total Thrust
The Boeing 707 has four engines, each providing a thrust of 75 kN. To find the total thrust, we multiply the thrust of one engine by the number of engines:
- Total thrust = Number of engines × Thrust per engine
- Total thrust = 4 × 75 kN = 300 kN
Since 1 kN is equal to 1,000 N, we convert this to Newtons:
- Total thrust = 300 kN = 300,000 N
Finding Acceleration
Next, we apply Newton's second law, which states that force equals mass times acceleration (F = ma). Rearranging this gives us acceleration (a) as:
Substituting the values we have:
- F = 300,000 N
- m = 1.2 × 105 kg
Now we can calculate the acceleration:
- a = 300,000 N / (1.2 × 105 kg)
- a = 2.5 m/s²
Determining Runway Length
To find the length of the runway needed for the aircraft to reach its takeoff speed of 73 m/s, we can use the kinematic equation:
Where:
- v = final velocity (takeoff speed) = 73 m/s
- u = initial velocity = 0 m/s (the aircraft starts from rest)
- a = acceleration = 2.5 m/s²
- s = distance (runway length)
Rearranging the equation to solve for s gives us:
Substituting the known values:
- s = (73 m/s)² / (2 × 2.5 m/s²)
- s = 5329 m²/s² / 5 m/s²
- s = 1065.8 m
Summary of Results
In conclusion, the Boeing 707 will experience an acceleration of 2.5 m/s², and it will require approximately 1065.8 meters of runway to reach its takeoff speed of 73 m/s. This calculation highlights the importance of thrust-to-weight ratio and acceleration in aviation, as they directly influence the performance and safety of aircraft during takeoff.