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Grade: 12th pass
        A body with mass m is acted by two forces F1 and F2 . if m=5.2kg, F1=3.7N, and F2=4.3N, find the vector acceleration of body?
one year ago

Answers : (4)

Piyush Kumar Behera
394 Points
							
Please specify the direction of the forcess acting on the body.Nor their will no fixed magnitude  nor direction of the acceleration vector.Please do repost the question!!
one year ago
Amna Saeed
24 Points
							Force f1 acts in upward direction and f2 towards the east ie right side direction. Both forces make an angle of 90 degree between each other. Now that direction are specified plz answer the question
						
one year ago
Hamza
10 Points
							F1 is in upward ( North ) and F2 is toward  right ( east ). Angle between F1 and F2 is 90°. Now answere this question please... Piyush Kumar.
						
one year ago
Piyush Kumar Behera
394 Points
							Ok ,in this question find the net acceleration in the north direction that is F1/m=3.7/5.2=0.711similarly find the net acceleration in the east dithat is that is F2/m=4.3/5.2=0.826.now if you know vectors then  as north and east direction are perpendicular so the net magnitude is√(0.711^2+0.826^2)=1.089(approx)this is from the formula of net magnitude of two vectors.Its direction is tan^-1(3.7/4.3) north of east.hope that helps !!please approve this solution to encourage me and if you don`t get the solution then please post it again here.. thanks
						
one year ago
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